Решите уравнение: (2x-5)^2-(2x-3)^2=0.

\[(2x - 5)^{2} - (2x - 3)^{2} = 0\]

\[(2x - 5 - 2x + 3)(2x - 5 + 2x - 3) = 0\]

\[- 2(4x - 8) = 0\]

\[- 2 \cdot 4(x - 2) = 0\]

\[x = 2.\]