\[ (x - 2)(x + 8) = x^2 + 8x - 2x - 16 = x^2 + 6x - 16 \]
\[ x^2 + 6x - 16 = 6x \]
\[ x^2 + 6x - 16 - 6x = 0 \]
\[ x^2 - 16 = 0 \]
\[ x^2 = 16 \]
\[ x = \pm 4 \]
Ответ: 4; -4