Решите уравнение: (x^2+6)/5-(8-x)/10=1.

\[\frac{x^{2} + 6}{5} - \frac{8 - x}{10} = 1\ \ | \cdot 10\]

\[2\left( x^{2} + 6 \right) - 8 + x = 10\]

\[2x^{2} + 12 - 8 + x - 10 = 0\]

\[2x^{2} + x - 6 = 0\]

\[D = 1 + 48 = 49\]

\[x_{1} = \frac{- 1 + 7}{4} = \frac{6}{4} = 1,5;\]

\[x_{2} = \frac{- 1 - 7}{4} = - 2.\]

\[Ответ:x = - 2;x = 1,5.\]