4. Решите уравнение: 1) 2x³- 50x = 0; 2) 16x³ + 8x² + x = 0; 3) x³ + 2x² - 36x - 72 = 0.

1) $$2x^3 - 50x = 0$$ $$2x(x^2 - 25) = 0$$ $$2x(x - 5)(x + 5) = 0$$ $$x = 0$$, $$x = 5$$, $$x = -5$$ 2) $$16x^3 + 8x^2 + x = 0$$ $$x(16x^2 + 8x + 1) = 0$$ $$x(4x + 1)^2 = 0$$ $$x = 0$$, $$x = -\frac{1}{4}$$ 3) $$x^3 + 2x^2 - 36x - 72 = 0$$ $$x^2(x + 2) - 36(x + 2) = 0$$ $$(x^2 - 36)(x + 2) = 0$$ $$(x - 6)(x + 6)(x + 2) = 0$$ $$x = 6$$, $$x = -6$$, $$x = -2$$ Ответ: 1) $$x = 0, x = 5, x = -5$$ 2) $$x = 0, x = -\frac{1}{4}$$ 3) $$x = 6, x = -6, x = -2$$