3. Решите уравнение: а) 13²-x²= 0 б) 9y² – 36 = 0 в) (3−x)²-x(x+1,5)=9

Решение: a) \(13^2 - x^2 = 0\) \(169 - x^2 = 0\) \(x^2 = 169\) \(x = \pm 13\) б) \(9y^2 - 36 = 0\) \(9y^2 = 36\) \(y^2 = 4\) \(y = \pm 2\) в) \((3 - x)^2 - x(x + 1.5) = 9\) \(9 - 6x + x^2 - x^2 - 1.5x = 9\) \(-7.5x = 0\) \(x = 0\)