5. Решите уравнение: A) (2x-5)² – (2x – 3)(2x + 3) = 0; Б) 9у² - 25 = 0,

Решим уравнения.

1. A) $$(2x-5)^2 - (2x-3)(2x+3) = 0$$
   $$4x^2 - 20x + 25 - (4x^2 - 9) = 0$$
   $$4x^2 - 20x + 25 - 4x^2 + 9 = 0$$
   $$-20x + 34 = 0$$
   $$-20x = -34$$
   $$x = \frac{-34}{-20} = \frac{17}{10} = 1,7$$
2. Б) $$9y^2 - 25 = 0$$
   $$9y^2 = 25$$
   $$y^2 = \frac{25}{9}$$
   $$y = \pm \sqrt{\frac{25}{9}} = \pm \frac{5}{3}$$
   $$y_1 = \frac{5}{3}, y_2 = -\frac{5}{3}$$

Ответ:

1. A) $$x = 1,7$$
2. Б) $$y_1 = \frac{5}{3}, y_2 = -\frac{5}{3}$$