Решите уравнение: a) $$(3x - 2)(3x + 2) - (3x - 8)² = 14x$$; б) $$25x² - 36 = 0$$.

a) $$(3x - 2)(3x + 2) - (3x - 8)^2 = 14x$$ $$9x^2 - 4 - (9x^2 - 48x + 64) = 14x$$ $$9x^2 - 4 - 9x^2 + 48x - 64 = 14x$$ $$48x - 68 = 14x$$ $$48x - 14x = 68$$ $$34x = 68$$ $$x = 2$$ б) $$25x^2 - 36 = 0$$ $$25x^2 = 36$$ $$x^2 = \frac{36}{25}$$ $$x = \pm \sqrt{\frac{36}{25}}$$ $$x = \pm \frac{6}{5}$$ **Ответ:** a) $$x = 2$$ б) $$x = \frac{6}{5}$$ или $$x = -\frac{6}{5}$$