Решите уравнение: (2y – 3)(3y + 1) + 2(y – 5)(y + 5) = 2(1-2y)² + 6y.

$$(2y - 3)(3y + 1) + 2(y - 5)(y + 5) = 2(1 - 2y)^2 + 6y$$

$$6y^2 + 2y - 9y - 3 + 2(y^2 - 25) = 2(1 - 4y + 4y^2) + 6y$$

$$6y^2 - 7y - 3 + 2y^2 - 50 = 2 - 8y + 8y^2 + 6y$$

$$8y^2 - 7y - 53 = 8y^2 - 2y + 2$$

$$-7y + 2y = 55$$

$$-5y = 55$$

$$y = -11$$

Ответ: $$y = -11$$