Решите уравнение: (2y-3)(3y+1)+2(y-5)(y+5)= 2(1-2y)² + 6y.

(2y - 3)(3y + 1) + 2(y - 5)(y + 5) = 2(1 - 2y)² + 6y

6y² + 2y - 9y - 3 + 2(y² - 25) = 2(1 - 4y + 4y²) + 6y

6y² - 7y - 3 + 2y² - 50 = 2 - 8y + 8y² + 6y

8y² - 7y - 53 = 8y² - 2y + 2

-7y + 2y = 2 + 53

-5y = 55

y = 55 / (-5)

y = -11