a) $$(2x^2-4x^2+7x+1) + (-x^2+2x^2+3x-5) =$$
$$2x^2-4x^2-x^2+2x^2 + 7x + 3x + 1 - 5 =$$
$$(2-4-1+2)x^2 + (7+3)x -4 = -x^2 + 10x - 4$$
б) $$(-10a^2+6a^3+3a) + (-6a^3-4a+8a^2) =$$
$$6a^3 - 6a^3 -10a^2 + 8a^2 + 3a - 4a = -2a^2 - a$$
в) $$(2a+b-c-d) + (4a-3b-2c+5d) =$$
$$2a + 4a + b - 3b - c - 2c - d + 5d = 6a - 2b - 3c + 4d$$
г) $$(x^2-y^2+x-6) + (-x^2+2y^2-y-4) =$$
$$x^2 - x^2 -y^2 + 2y^2 + x - y - 6 - 4 = y^2 + x - y - 10$$
Ответ: a) $$-x^2 + 10x - 4$$, б) $$-2a^2 - a$$, в) $$6a - 2b - 3c + 4d$$, г) $$y^2 + x - y - 10$$