Сократите дробь: 1) (√a+7)/(a-49); 2) (33-√33)/√33; 3) (a-2√3a +3)/(a-3)

<ol> <li>1) $$\frac{\sqrt{a} + 7}{a - 49} = \frac{\sqrt{a} + 7}{(\sqrt{a} - 7)(\sqrt{a} + 7)} = \frac{1}{\sqrt{a} - 7}$$</li> <li>2) $$\frac{33 - \sqrt{33}}{\sqrt{33}} = \frac{\sqrt{33} \cdot \sqrt{33} - \sqrt{33}}{\sqrt{33}} = \frac{\sqrt{33}(\sqrt{33} - 1)}{\sqrt{33}} = \sqrt{33} - 1$$</li> <li>3) $$\frac{a - 2\sqrt{3a} + 3}{a - 3} = \frac{(\sqrt{a})^2 - 2\sqrt{3}\sqrt{a} + (\sqrt{3})^2}{(\sqrt{a})^2 - (\sqrt{3})^2} = \frac{(\sqrt{a} - \sqrt{3})^2}{(\sqrt{a} - \sqrt{3})(\sqrt{a} + \sqrt{3})} = \frac{\sqrt{a} - \sqrt{3}}{\sqrt{a} + \sqrt{3}}$$</li> </ol> <strong>Ответ:</strong><br> 1) $$\frac{1}{\sqrt{a} - 7}$$<br> 2) $$\sqrt{33} - 1$$<br> 3) $$\frac{\sqrt{a} - \sqrt{3}}{\sqrt{a} + \sqrt{3}}$$