Сократите дроби: \(\frac{10}{5},\frac{12}{18},\frac{24}{48},\frac{28}{35}\); а) \(\frac{8\cdot11}{33\cdot4}\); б) \(\frac{18\cdot25}{75\cdot12}\); в) \(\frac{6\cdot7+7}{49}\).

\(\frac{10}{5}=2\); \(\frac{12}{18}=\frac{2}{3}\); \(\frac{24}{48}=\frac{1}{2}\); \(\frac{28}{35}=\frac{4}{5}\).

а) \(\frac{8\cdot11}{33\cdot4}=\frac{2\cdot11}{33}=\frac{22}{33}=\frac{2}{3}\).

б) \(\frac{18\cdot25}{75\cdot12}=\frac{18}{3\cdot12}=\frac{18}{36}=\frac{1}{2}\).

в) \(\frac{6\cdot7+7}{49}=\frac{42+7}{49}=\frac{49}{49}=1\).

Ответ: \(2;\frac{2}{3};\frac{1}{2};\frac{4}{5};\frac{2}{3};\frac{1}{2};1\).