1) Упростим выражение:
$$\frac{a + 9}{3a + 9} - \frac{a + 3}{3a - 9} + \frac{13}{a^2 - 9} = \frac{a + 9}{3(a + 3)} - \frac{a + 3}{3(a - 3)} + \frac{13}{(a - 3)(a + 3)} = \frac{(a + 9)(a - 3) - (a + 3)^2 + 39}{3(a - 3)(a + 3)} = \frac{a^2 + 6a - 27 - a^2 - 6a - 9 + 39}{3(a - 3)(a + 3)} = \frac{3}{3(a - 3)(a + 3)} = \frac{1}{a^2 - 9}$$
Ответ:$$\frac{1}{a^2-9}$$