a) 1,6x-1y12 ⋅ 5x3y-11 при x = -0,2, y = 0,7
Сначала упростим выражение: 1,6 ⋅ 5 ⋅ x-1+3 ⋅ y12+(-11) = 8 ⋅ x2 ⋅ y1 = 8x2y
Подставим значения: 8 ⋅ (-0,2)2 ⋅ 0,7 = 8 ⋅ 0,04 ⋅ 0,7 = 8 ⋅ 0,028 = 0,224
б) \(\frac{5}{6}\)x-3y3 ⋅ 30x3y-4 при x = 127, y = \(\frac{1}{5}\)
Сначала упростим выражение: \(\frac{5}{6}\) ⋅ 30 ⋅ x-3+3 ⋅ y3+(-4) = 25 ⋅ x0 ⋅ y-1 = 25 ⋅ 1 ⋅ y-1 = \(\frac{25}{y}\)
Подставим значения: \(\frac{25}{\frac{1}{5}}\) = 25 ⋅ 5 = 125
Ответ: a) 0,224, б) 125