a) 1,5ab-3 ⋅ 6a-2b = 1,5 ⋅ 6 ⋅ a1+(-2) ⋅ b-3+1 = 9a-1b-2 = \(\frac{9}{ab^2}\)
б) \(\frac{3}{4}\)m-2n4 ⋅ 8m3n-2 = \(\frac{3}{4}\) ⋅ 8 ⋅ m-2+3 ⋅ n4+(-2) = 6m1n2 = 6mn2
в) 0,6c2d4 ⋅ \(\frac{1}{3}\)c-2d-4 = 0,6 ⋅ \(\frac{1}{3}\) ⋅ c2+(-2) ⋅ d4+(-4) = 0,2c0d0 = 0,2 ⋅ 1 ⋅ 1 = 0,2
г) 3,2x-1y-5 ⋅ \(\frac{5}{8}\)xy = 3,2 ⋅ \(\frac{5}{8}\) ⋅ x-1+1 ⋅ y-5+1 = 2x0y-4 = 2 ⋅ 1 ⋅ y-4 = \(\frac{2}{y^4}\)
д) \(\frac{1}{2}\)p-1q-3 ⋅ \(\frac{1}{6}\)p2q3 = \(\frac{1}{2}\) ⋅ \(\frac{1}{6}\) ⋅ p-1+2 ⋅ q-3+3 = \(\frac{1}{12}\)p1q0 = \(\frac{1}{12}\)p ⋅ 1 = \(\frac{p}{12}\)
e) 3\(\frac{1}{3}\)a5b-18 ⋅ 0,6a-1b20 = \(\frac{10}{3}\) ⋅ 0,6 ⋅ a5+(-1) ⋅ b-18+20 = 2a4b2