a) $$6\sqrt{3} + \sqrt{27} - 3\sqrt{75} = 6\sqrt{3} + \sqrt{9\cdot3} - 3\sqrt{25\cdot3} = 6\sqrt{3} + 3\sqrt{3} - 3\cdot 5\sqrt{3} = 6\sqrt{3} + 3\sqrt{3} - 15\sqrt{3} = (6+3-15)\sqrt{3} = -6\sqrt{3}$$
Ответ: $$-6\sqrt{3}$$
б) $$(\sqrt{50} - 2\sqrt{2})\sqrt{2} = \sqrt{50}\cdot\sqrt{2} - 2\sqrt{2}\cdot\sqrt{2} = \sqrt{100} - 2 \cdot 2 = 10 - 4 = 6$$
Ответ: 6
в) $$(2-\sqrt{3})^2 = 2^2 - 2\cdot2\cdot\sqrt{3} + (\sqrt{3})^2 = 4 - 4\sqrt{3} + 3 = 7 - 4\sqrt{3}$$
Ответ: $$7 - 4\sqrt{3}$$