a) $$\left(\frac{1}{3}a^5y^3\right)^2 \cdot (-ay)^3 = \frac{1}{9}a^{10}y^6 \cdot (-a^3y^3) = -\frac{1}{9}a^{10+3}y^{6+3} = -\frac{1}{9}a^{13}y^9$$
б) $$-0.1a^4b^7 \cdot (-30a^2b)^2 = -0.1a^4b^7 \cdot 900a^4b^2 = -90a^{4+4}b^{7+2} = -90a^8b^9$$
Ответ: а) $$\frac{-1}{9}a^{13}y^9$$, б) $$-90a^8b^9$$