2. Упростите выражение: 3a a+2 1) a-4 2a-8 a² + 2a

1) \[\frac{3a}{a-4} - \frac{a+2}{2a-8} \cdot \frac{96}{a^2 + 2a} = \frac{3a}{a-4} - \frac{a+2}{2(a-4)} \cdot \frac{96}{a(a+2)} = \frac{3a}{a-4} - \frac{(a+2) \cdot 96}{2(a-4) \cdot a(a+2)} = \frac{3a}{a-4} - \frac{48}{a(a-4)} = \frac{3a^2 - 48}{a(a-4)} = \frac{3(a^2 - 16)}{a(a-4)} = \frac{3(a-4)(a+4)}{a(a-4)} = \frac{3(a+4)}{a}\]