a)
$$\frac{c-1}{12c} + \frac{2c+7}{12c} - \frac{6-3c}{12c} = \frac{c - 1 + 2c + 7 - 6 + 3c}{12c} = \frac{6c}{12c} = \frac{1}{2}$$
б)
$$\frac{a-4b}{2ab} + \frac{2a-6b}{2ab} - \frac{3a-b}{2ab} = \frac{a - 4b + 2a - 6b - 3a + b}{2ab} = \frac{-9b}{2ab} = -\frac{9}{2a}$$
в)
$$\frac{17x-4y}{21xy} + \frac{8x+9y}{21xy} - \frac{11x-16y}{21xy} = \frac{17x - 4y + 8x + 9y - 11x + 16y}{21xy} = \frac{14x + 21y}{21xy} = \frac{7(2x + 3y)}{21xy} = \frac{2x + 3y}{3xy}$$
Ответ: a) 1/2, б) -9/(2a), в) (2x+3y)/(3xy)