a) $$2\sqrt{2} + \sqrt{50} - \sqrt{98} = 2\sqrt{2} + \sqrt{25 \cdot 2} - \sqrt{49 \cdot 2} = 2\sqrt{2} + 5\sqrt{2} - 7\sqrt{2} = 0$$.
б) $$(3\sqrt{5} - \sqrt{20})\sqrt{5} = (3\sqrt{5} - \sqrt{4 \cdot 5})\sqrt{5} = (3\sqrt{5} - 2\sqrt{5})\sqrt{5} = \sqrt{5} \cdot \sqrt{5} = 5$$.
в) $$\left(\sqrt{3} + \sqrt{2}\right)^2 = \left(\sqrt{3}\right)^2 + 2\sqrt{3}\sqrt{2} + \left(\sqrt{2}\right)^2 = 3 + 2\sqrt{6} + 2 = 5 + 2\sqrt{6}$$.
Ответ: a) 0; б) 5; в) $$5 + 2\sqrt{6}$$.