в) $$\left(14\frac{2}{3}-5\frac{5}{9}\right)-\left(3\frac{7}{8}+4\frac{5}{6}\right)+1\frac{1}{12}$$;

в) $$\left(14\frac{2}{3}-5\frac{5}{9}\right)-\left(3\frac{7}{8}+4\frac{5}{6}\right)+1\frac{1}{12}=\left(14\frac{6}{9}-5\frac{5}{9}\right)-\left(3\frac{21}{24}+4\frac{20}{24}\right)+1\frac{1}{12}=9\frac{1}{9}-8\frac{41}{24}+1\frac{1}{12}=9\frac{1}{9}-9\frac{17}{24}+1\frac{1}{12}=-\frac{17}{24}+\frac{1}{9}+1\frac{1}{12}=-\frac{51}{72}+\frac{8}{72}+1\frac{6}{72}=-\frac{43}{72}+1\frac{6}{72}=\frac{29}{72}+\frac{78}{72}=\frac{35}{72}$$

Ответ: $$\frac{35}{72}$$