В1. Решите уравнение (x+1)² (x-1)² x²-1 6 + 12 - 4 =1.

$$ \frac{(x+1)^2}{6} + \frac{(x-1)^2}{12} - \frac{x^2-1}{4} = 1 $$

$$ \frac{2(x+1)^2 + (x-1)^2 - 3(x^2-1)}{12} = 1 $$

$$ 2(x^2 + 2x + 1) + x^2 - 2x + 1 - 3x^2 + 3 = 12 $$

$$ 2x^2 + 4x + 2 + x^2 - 2x + 1 - 3x^2 + 3 = 12 $$

$$ 4x + 6 = 12 $$

$$ 4x = 6 $$

$$ x = \frac{6}{4} = \frac{3}{2} = 1.5 $$

Ответ: $$ 1.5 $$