В1. Решите уравнение (x+2)² x²-4 (x-2)² x² 2 - 4 - 8 = 8

$$ \frac{(x+2)^2}{2} - \frac{x^2-4}{4} - \frac{(x-2)^2}{8} = \frac{x^2}{8} $$

$$ \frac{4(x+2)^2 - 2(x^2-4) - (x-2)^2}{8} = \frac{x^2}{8} $$

$$ 4(x^2+4x+4) - 2x^2 + 8 - (x^2 - 4x + 4) = x^2 $$

$$ 4x^2 + 16x + 16 - 2x^2 + 8 - x^2 + 4x - 4 = x^2 $$

$$ x^2 + 20x + 20 = x^2 $$

$$ 20x = -20 $$

$$ x = -1 $$

Ответ: $$ -1 $$