1. Найдем значение выражения:
- а) $$7\frac{11}{12}:3\frac{2}{3}=\frac{7\cdot12+11}{12}:\frac{3\cdot3+2}{3}=\frac{84+11}{12}:\frac{9+2}{3}=\frac{95}{12}:\frac{11}{3}=\frac{95}{12}\cdot\frac{3}{11}=\frac{95\cdot3}{12\cdot11}=\frac{95\cdot1}{4\cdot11}=\frac{95}{44}=2\frac{7}{44}$$
- б) $$2\frac{3}{5}:4\frac{4}{15}=\frac{2\cdot5+3}{5}:\frac{4\cdot15+4}{15}=\frac{10+3}{5}:\frac{60+4}{15}=\frac{13}{5}:\frac{64}{15}=\frac{13}{5}\cdot\frac{15}{64}=\frac{13\cdot15}{5\cdot64}=\frac{13\cdot3}{1\cdot64}=\frac{39}{64}$$
- в) $$20,4:3,4=\frac{204}{10}:\frac{34}{10}=\frac{204}{10}\cdot\frac{10}{34}=\frac{204\cdot10}{10\cdot34}=\frac{204}{34}=6$$
- г) $$1,71:\frac{4}{15}=\frac{171}{100}:\frac{4}{15}=\frac{171}{100}\cdot\frac{15}{4}=\frac{171\cdot15}{100\cdot4}=\frac{171\cdot3}{20\cdot4}=\frac{513}{80}=6\frac{33}{80}$$
Ответ: а) $$2\frac{7}{44}$$, б) $$\frac{39}{64}$$, в) $$6$$, г) $$6\frac{33}{80}$$