а) \(1\frac57:\,1\frac17=\frac{12}{7}:\frac87=\frac{12}{7}\cdot\frac78=\frac32=1\frac12\).
б) \(3\frac15:\,2\frac{2}{15}=\frac{16}{5}:\frac{32}{15}=\frac{16}{5}\cdot\frac{15}{32}=\frac32=1\frac12\).
в) \(5\frac23:\frac13-1\frac7{12}\cdot6=\frac{17}{3}\cdot3-\frac{19}{12}\cdot6=17-\frac{19}{2}=\frac{15}{2}=7\frac12\).
Ответ: а) \(1\frac12\); б) \(1\frac12\); в) \(7\frac12\).