Ответ:
\(11\frac{2}{3}-8\frac{3}{4}=\frac{140}{12}-\frac{105}{12}=\frac{35}{12}\).
\(3\frac{1}{3}+2\frac{5}{6}=\frac{20}{6}+\frac{17}{6}=\frac{37}{6}=\frac{74}{12}\).
\(\frac{35}{12}+\frac{74}{12}-\frac{55}{12}=\frac{54}{12}=4\frac{1}{2}\).
Ответ: \(4\frac{1}{2}\).
