Ответ:

\(3\frac{1}{4}-2\frac{2}{3}=\frac{13}{4}-\frac{8}{3}=\frac{39-32}{12}=\frac{7}{12}\).

\(1\frac{5}{6}-1\frac{7}{12}=\frac{22}{12}-\frac{19}{12}=\frac{3}{12}=\frac{1}{4}\).

\(\frac{7}{12}\cdot\frac{1}{4}+3\frac{5}{24}=\frac{7}{48}+\frac{77}{24}=\frac{7}{48}+\frac{154}{48}=\frac{161}{48}=3\frac{17}{48}\).

Ответ: \(3\frac{17}{48}\).