Ответ:\(\dfrac{3^7\cdot(3^3)^2}{3^{11}}=3^{7+6-11}=3^2=9\).\(\dfrac{(2^4)^8}{2^{18}\cdot2^{16}}=2^{32-18-16}=2^{-2}=\dfrac14\).\(\dfrac{(5^2)^4\cdot25}{5^{10}\cdot5}=\dfrac{5^8\cdot5^2}{5^{11}}=5^{-1}=\dfrac15\).