Вариант 4. Выполните действия: б) \(1\frac{4}{11}\cdot3\frac{1}{7}:3\frac{4}{7}\); в) \(2\frac{2}{5}:(3\frac{2}{5}-1\frac{11}{15})\); г) \(1\frac{8}{9}:(3\frac{1}{6}-1\frac{3}{4})\); д) \(6\frac{3}{8}\cdot1\frac{7}{17}-2\frac{3}{8}:1\frac{1}{4}+\frac{2}{5}\); е) \(10-2\frac{1}{2}:\frac{3}{4}+(2\frac{1}{2}-1\frac{1}{3})\cdot6\).

б) \(1\frac{4}{11}=\frac{15}{11}\), \(3\frac{1}{7}=\frac{22}{7}\), \(3\frac{4}{7}=\frac{25}{7}\).

\(\frac{15}{11}\cdot\frac{22}{7}:\frac{25}{7}=\frac{15}{11}\cdot\frac{22}{25}=\frac{6}{5}\).

в) \(3\frac{2}{5}-1\frac{11}{15}=\frac{17}{5}-\frac{26}{15}=\frac{25}{15}=\frac{5}{3}\).
\(2\frac{2}{5}:\frac{5}{3}=\frac{12}{5}\cdot\frac{3}{5}=\frac{36}{25}=1\frac{11}{25}\).

г) \(3\frac{1}{6}-1\frac{3}{4}=\frac{19}{6}-\frac{7}{4}=\frac{17}{12}\).
\(1\frac{8}{9}:\frac{17}{12}=\frac{17}{9}\cdot\frac{12}{17}=\frac{4}{3}=1\frac{1}{3}\).

д) \(6\frac{3}{8}\cdot1\frac{7}{17}=\frac{51}{8}\cdot\frac{24}{17}=9\).
\(2\frac{3}{8}:1\frac{1}{4}=\frac{19}{8}\cdot\frac{4}{5}=\frac{19}{10}\).
\(9-\frac{19}{10}+\frac{2}{5}=\frac{90-19+4}{10}=\frac{75}{10}=\frac{15}{2}=7\frac{1}{2}\).

е) \(2\frac{1}{2}:\frac{3}{4}=\frac{5}{2}\cdot\frac{4}{3}=\frac{10}{3}\).
\(2\frac{1}{2}-1\frac{1}{3}=\frac{5}{2}-\frac{4}{3}=\frac{7}{6}\), поэтому \(\frac{7}{6}\cdot6=7\).
\(10-\frac{10}{3}+7=17-\frac{10}{3}=\frac{41}{3}=13\frac{2}{3}\).

Ответ: б) \(\frac{6}{5}\); в) \(1\frac{11}{25}\); г) \(1\frac{1}{3}\); д) \(7\frac{1}{2}\); е) \(13\frac{2}{3}\).