Ответ:
- \(\cos 60^\circ+\cos 120^\circ=\frac12-\frac12=0\).
- \(\sin 150^\circ\cdot\sin 30^\circ=\frac12\cdot\frac12=\frac14\).
- \( g 150^\circ+ g 30^\circ=-\frac{1}{\sqrt3}+\frac{1}{\sqrt3}=0\).
- \(\cos 120^\circ-\sin 60^\circ=-\frac12-\frac{\sqrt3}{2}=-\frac{1+\sqrt3}{2}\).
- \(\sin 135^\circ\cdot\cos 45^\circ=\frac{\sqrt2}{2}\cdot\frac{\sqrt2}{2}=\frac12\).
