Ответ:
- \(\cos 45^\circ+\cos 135^\circ=\frac{\sqrt2}{2}-\frac{\sqrt2}{2}=0\).
- \(\sin 120^\circ\cdot\cos 60^\circ=\frac{\sqrt3}{2}\cdot\frac12=\frac{\sqrt3}{4}\).
- \( g 120^\circ\cdot g 60^\circ=(-\sqrt3)\cdot\sqrt3=-3\).
- \(\cos 150^\circ-\cos 30^\circ=-\frac{\sqrt3}{2}-\frac{\sqrt3}{2}=-\sqrt3\).
- \(\sin 150^\circ\cdot\sin 120^\circ=\frac12\cdot\frac{\sqrt3}{2}=\frac{\sqrt3}{4}\).
