Ответ:
- \(\sin 60^\circ-\sin 120^\circ=\frac{\sqrt3}{2}-\frac{\sqrt3}{2}=0\).
- \(\cos 150^\circ\cdot\cos 30^\circ=-\frac{\sqrt3}{2}\cdot\frac{\sqrt3}{2}=-\frac34\).
- \( g 135^\circ\cdot g 150^\circ=(-1)\cdot\left(-\frac{1}{\sqrt3}\right)=\frac{\sqrt3}{3}\).
- \(\sin 120^\circ+\sin 150^\circ=\frac{\sqrt3}{2}+\frac12=\frac{\sqrt3+1}{2}\).
- \(\cos 135^\circ\cdot\sin 135^\circ=-\frac{\sqrt2}{2}\cdot\frac{\sqrt2}{2}=-\frac12\).
