5.355 Вычислите: 1) \(\frac{5}{13}+\frac{4}{13}\) 2) \(\frac{9}{25}-\frac{6}{25}+\frac{2}{25}\) 3) \(5\frac{5}{7}-4\frac{1}{4}+3\frac{3}{4}\) 4) \(9\frac{5}{14}+1\frac{13}{14}-8\frac{1}{6}\)

1. \(\frac{5}{13}+\frac{4}{13}=\frac{5+4}{13}=\frac{9}{13}\)
2. \(\frac{9}{25}-\frac{6}{25}+\frac{2}{25}=\frac{9-6+2}{25}=\frac{5}{25}=\frac{1}{5}\)
3. \(5\frac{5}{7}-4\frac{1}{4}+3\frac{3}{4}=5\frac{5}{7}+3\frac{3}{4}-4\frac{1}{4}=8\frac{5}{7}+\frac{3}{4}-\frac{1}{4}=8\frac{5}{7}+\frac{3-1}{4}=8\frac{5}{7}+\frac{2}{4}=8\frac{5}{7}+\frac{1}{2}=8\frac{10}{14}+\frac{7}{14}=8\frac{17}{14}=9\frac{3}{14}\)
4. \(9\frac{5}{14}+1\frac{13}{14}-8\frac{1}{6}=9\frac{5}{14}+1\frac{13}{14}-8\frac{1}{6}=10\frac{5+13}{14}-8\frac{1}{6}=10\frac{18}{14}-8\frac{1}{6}=10\frac{9}{7}-8\frac{1}{6}=11\frac{2}{7}-8\frac{1}{6}=11\frac{12}{42}-8\frac{7}{42}=3\frac{5}{42}\)

Ответ: 1) \(\frac{9}{13}\); 2) \(\frac{1}{5}\); 3) \(9\frac{3}{14}\); 4) \(3\frac{5}{42}\)