- a) \(6\frac{14}{18}-5\frac{5}{18} = (6-5) + (\frac{14}{18}-\frac{5}{18}) = 1 + \frac{14-5}{18} = 1 + \frac{9}{18} = 1 + \frac{1}{2} = 1\frac{1}{2}\)
- б) \(6\frac{5}{22}+5\frac{6}{22} = (6+5) + (\frac{5}{22}+\frac{6}{22}) = 11 + \frac{5+6}{22} = 11 + \frac{11}{22} = 11 + \frac{1}{2} = 11\frac{1}{2}\)
- в) \(6\frac{7}{12}-1\frac{3}{12} = (6-1) + (\frac{7}{12}-\frac{3}{12}) = 5 + \frac{7-3}{12} = 5 + \frac{4}{12} = 5 + \frac{1}{3} = 5\frac{1}{3}\)
- г) \(7\frac{7}{5}+3\frac{4}{5} = (7+3) + (\frac{7}{5}+\frac{4}{5}) = 10 + \frac{7+4}{5} = 10 + \frac{11}{5} = 10 + 2\frac{1}{5} = 12\frac{1}{5}\)
Ответ: a) \(1\frac{1}{2}\); б) \(11\frac{1}{2}\); в) \(5\frac{1}{3}\); г) \(12\frac{1}{5}\)