2. Вычислите: 4$$\frac{1}{6}\cdot 3\frac{6}{7}+2\frac{6}{7}\cdot 4\frac{1}{6}

Решение:

4$$\frac{1}{6}\cdot$$3$$\frac{6}{7}$$+2$$\frac{6}{7}\cdot$$4$$\frac{1}{6}$$ = 4$$\frac{1}{6}\cdot$$3$$\frac{6}{7}$$+4$$\frac{1}{6}\cdot$$2$$\frac{6}{7}$$ = 4$$\frac{1}{6}$$ $$\cdot$$ (3$$\frac{6}{7}$$ + 2$$\frac{6}{7}$$) = 4$$\frac{1}{6}$$ $$\cdot$$ 6$$\frac{12}{7}$$ = $$\frac{25}{6} \cdot \frac{54}{7}$$ = $$\frac{25 \cdot 6 \cdot 9}{6 \cdot 7}$$ = $$\frac{225}{7}$$ = 32$$\frac{1}{7}$$

Ответ: 32$$\frac{1}{7}$$