2. Вычислите: $$\frac{3}{4}+(-8\frac{3}{5}+4\frac{6}{5}\cdot\frac{1}{6}):\frac{8}{25}$$. Запишите полностью решение и ответ.

1) $$4\frac{6}{5}=\frac{4\cdot5+6}{5}=\frac{26}{5}$$

2) $$\frac{26}{5}\cdot\frac{1}{6}=\frac{13}{15}$$

3) $$-8\frac{3}{5}=-\frac{8\cdot5+3}{5}=-\frac{43}{5}$$

4) $$-\frac{43}{5}+\frac{13}{15}=-\frac{43\cdot3}{5\cdot3}+\frac{13}{15}=-\frac{129}{15}+\frac{13}{15}=-\frac{116}{15}$$

5) $$-\frac{116}{15}:\frac{8}{25}=-\frac{116}{15}\cdot\frac{25}{8}=-\frac{29\cdot5}{3\cdot2}=-\frac{145}{6}$$

6) $$\frac{3}{4}+(-\frac{145}{6})=\frac{3\cdot3}{4\cdot3}-\frac{145\cdot2}{6\cdot2}=\frac{9}{12}-\frac{290}{12}=-\frac{281}{12}=-23\frac{5}{12}$$

Ответ: $$-23\frac{5}{12}$$