14. Вычислите: 2-\frac{1}{3}+\frac{4}{9} \cdot 3-\frac{3}{8} - 1\frac{6}{7}:\frac{26}{63}.

Разбираемся:

Пошаговое решение:

1. \(2\frac{1}{3} = \frac{7}{3}\)
2. \(\frac{4}{9} \cdot 3 = \frac{4}{9} \cdot \frac{3}{1} = \frac{12}{9} = \frac{4}{3}\)
3. \(1\frac{6}{7} = \frac{13}{7}\)
4. \(\frac{13}{7} : \frac{26}{63} = \frac{13}{7} \cdot \frac{63}{26} = \frac{13 \cdot 63}{7 \cdot 26} = \frac{1 \cdot 9}{1 \cdot 2} = \frac{9}{2} = 4\frac{1}{2}\)
5. \(\frac{7}{3} + \frac{4}{3} = \frac{11}{3} = 3\frac{2}{3}\)
6. \(3\frac{2}{3} - \frac{3}{8} = \frac{11}{3} - \frac{3}{8} = \frac{88}{24} - \frac{9}{24} = \frac{79}{24} = 3\frac{7}{24}\)
7. \(3\frac{7}{24} - 4\frac{1}{2} = \frac{79}{24} - \frac{9}{2} = \frac{79}{24} - \frac{108}{24} = -\frac{29}{24} = -1\frac{5}{24}\)

Ответ: -1\(\frac{5}{24}\)