Вычислите: 5) $$(2\frac{13}{48}+2\frac{5}{12}):3\frac{3}{4} - 9\frac{3}{4}:12$$

1) $$2\frac{13}{48} + 2\frac{5}{12} = 2\frac{13}{48} + 2\frac{20}{48} = 4\frac{33}{48} = 4\frac{11}{16} = \frac{4 \cdot 16 + 11}{16} = \frac{64 + 11}{16} = \frac{75}{16}$$

2) $$3\frac{3}{4} = \frac{3 \cdot 4 + 3}{4} = \frac{12 + 3}{4} = \frac{15}{4}$$

3) $$\frac{75}{16} : \frac{15}{4} = \frac{75}{16} \cdot \frac{4}{15} = \frac{5 \cdot 1}{4 \cdot 1} = \frac{5}{4}$$

4) $$9\frac{3}{4} = \frac{9 \cdot 4 + 3}{4} = \frac{36 + 3}{4} = \frac{39}{4}$$

5) $$\frac{39}{4} : 12 = \frac{39}{4} \cdot \frac{1}{12} = \frac{13 \cdot 1}{4 \cdot 4} = \frac{13}{16}$$

6) $$\frac{5}{4} - \frac{13}{16} = \frac{5 \cdot 4}{4 \cdot 4} - \frac{13}{16} = \frac{20}{16} - \frac{13}{16} = \frac{7}{16}$$

Ответ: $$\frac{7}{16}$$