\[\frac{7}{12}+\frac{5}{6}=\frac{7}{12}+\frac{10}{12}=\frac{17}{12},\qquad 2\frac{5}{6}=\frac{17}{6}.\]
\[\left(\frac{17}{12}\right):\left(\frac{17}{6}\right)=\frac{17}{12}\cdot\frac{6}{17}=\frac{1}{2}.\]
Тогда
\[-1+\frac{1}{2}-\frac{2}{3}=-\frac{1}{2}-\frac{2}{3}=-\frac{3}{6}-\frac{4}{6}=-\frac{7}{6}=-1\frac{1}{6}.\]
Ответ: \(-1\frac{1}{6}\).