Решение:
\[ \left(-\frac{5}{2}\right)^3 \times \left(\frac{4}{5}\right)^2 \]
\[ \left(-\frac{5}{2}\right)^3 = -\frac{5^3}{2^3} = -\frac{125}{8} \]
\[ \left(\frac{4}{5}\right)^2 = \frac{4^2}{5^2} = \frac{16}{25} \]
\[ -\frac{125}{8} \times \frac{16}{25} \]
\[ -\frac{\cancel{125}^5}{\cancel{8}^1} \times \frac{\cancel{16}^2}{\cancel{25}^1} = -5 \times 2 = -10 \]
Ответ: -10