a) $$\sqrt{\frac{25}{64}} = \frac{\sqrt{25}}{\sqrt{64}} = \frac{5}{8}$$
б) $$\sqrt{28} \cdot \sqrt{63} = \sqrt{28 \cdot 63} = \sqrt{4 \cdot 7 \cdot 9 \cdot 7} = \sqrt{4 \cdot 9 \cdot 7^2} = 2 \cdot 3 \cdot 7 = 42$$
в) $$2(\sqrt{3})^2 = 2 \cdot 3 = 6$$
г) $$\sqrt{54 \cdot 72} = \sqrt{2 \cdot 27 \cdot 8 \cdot 9} = \sqrt{2 \cdot 3^3 \cdot 2^3 \cdot 3^2} = \sqrt{2^4 \cdot 3^5} = \sqrt{2^4 \cdot 3^4 \cdot 3} = 2^2 \cdot 3^2 \cdot \sqrt{3} = 4 \cdot 9 \cdot \sqrt{3} = 36\sqrt{3}$$