Ответ:
- \(2.9(7.83+5.07-2.9)=2.9\cdot10=29\).
- \(\frac7{11}\cdot27.25+\frac{23}{4}:\frac{11}{7}=\frac7{11}\cdot\frac{109}{4}+\frac{23}{4}\cdot\frac7{11}=\frac7{11}\cdot\frac{132}{4}=21\).
- \(4.97\cdot5.03=(5-0.03)(5+0.03)=25-0.0009=24.9991\).
- \(\frac97\cdot\frac{431}{25}-3.24\cdot\frac97=\frac97(17.24-3.24)=\frac97\cdot14=18\).
