Вычислите: a) 2 + \frac{1}{3}; b) 1 + \frac{1}{2}; c) 3 + \frac{4}{9}; d) 6 + \frac{1}{3}; e) 1 + \frac{1}{3}; f) 6 + \frac{3}{5}; g) 15 - \frac{7}{10}; h) 11 + \frac{3}{5}; i) 8 + \frac{5}{12}; j) 5 - \frac{1}{6}; k) 30 - \frac{3}{6}; l) 35 - \frac{4}{15}.

Решение: a) 2 + \frac{1}{3} = \frac{2*3}{3} + \frac{1}{3} = \frac{6}{3} + \frac{1}{3} = \frac{7}{3} = 2\frac{1}{3} b) 1 + \frac{1}{2} = \frac{1*2}{2} + \frac{1}{2} = \frac{2}{2} + \frac{1}{2} = \frac{3}{2} = 1\frac{1}{2} c) 3 + \frac{4}{9} = \frac{3*9}{9} + \frac{4}{9} = \frac{27}{9} + \frac{4}{9} = \frac{31}{9} = 3\frac{4}{9} d) 6 + \frac{1}{3} = \frac{6*3}{3} + \frac{1}{3} = \frac{18}{3} + \frac{1}{3} = \frac{19}{3} = 6\frac{1}{3} e) 1 + \frac{1}{3} = \frac{1*3}{3} + \frac{1}{3} = \frac{3}{3} + \frac{1}{3} = \frac{4}{3} = 1\frac{1}{3} f) 6 + \frac{3}{5} = \frac{6*5}{5} + \frac{3}{5} = \frac{30}{5} + \frac{3}{5} = \frac{33}{5} = 6\frac{3}{5} g) 15 - \frac{7}{10} = \frac{15*10}{10} - \frac{7}{10} = \frac{150}{10} - \frac{7}{10} = \frac{143}{10} = 14\frac{3}{10} h) 11 + \frac{3}{5} = \frac{11*5}{5} + \frac{3}{5} = \frac{55}{5} + \frac{3}{5} = \frac{58}{5} = 11\frac{3}{5} i) 8 + \frac{5}{12} = \frac{8*12}{12} + \frac{5}{12} = \frac{96}{12} + \frac{5}{12} = \frac{101}{12} = 8\frac{5}{12} j) 5 - \frac{1}{6} = \frac{5*6}{6} - \frac{1}{6} = \frac{30}{6} - \frac{1}{6} = \frac{29}{6} = 4\frac{5}{6} k) 30 - \frac{3}{6} = \frac{30*6}{6} - \frac{3}{6} = \frac{180}{6} - \frac{3}{6} = \frac{177}{6} = 29\frac{3}{6} = 29\frac{1}{2} l) 35 - \frac{4}{15} = \frac{35*15}{15} - \frac{4}{15} = \frac{525}{15} - \frac{4}{15} = \frac{521}{15} = 34\frac{11}{15}