a) \(\frac{27}{35} \cdot \frac{7}{9} - \frac{9}{24} \cdot \frac{6}{45}\)
- \(\frac{27}{35} \cdot \frac{7}{9} = \frac{27 \cdot 7}{35 \cdot 9} = \frac{3 \cdot 1}{5 \cdot 1} = \frac{3}{5}\)
- \(\frac{9}{24} \cdot \frac{6}{45} = \frac{9 \cdot 6}{24 \cdot 45} = \frac{1 \cdot 1}{4 \cdot 5} = \frac{1}{20}\)
- \(\frac{3}{5} - \frac{1}{20} = \frac{3 \cdot 4}{5 \cdot 4} - \frac{1}{20} = \frac{12}{20} - \frac{1}{20} = \frac{12-1}{20} = \frac{11}{20}\)
Ответ: \(\frac{11}{20}\)