4) y = 1/(4x+6)^3

4) \(y = \frac{1}{(4x+6)^3} = (4x+6)^{-3}\) \(y' = -3(4x+6)^{-4} \cdot (4x+6)' = -3(4x+6)^{-4} \cdot 4 = -12(4x+6)^{-4} = \frac{-12}{(4x+6)^4}\) Ответ: \(y' = \frac{-12}{(4x+6)^4}\)