5) y = 5/(10-5x)^6

5) \(y = \frac{5}{(10-5x)^6} = 5(10-5x)^{-6}\) \(y' = 5 \cdot (-6) (10-5x)^{-7} \cdot (10-5x)' = -30(10-5x)^{-7} \cdot (-5) = 150(10-5x)^{-7} = \frac{150}{(10-5x)^7}\) Ответ: \(y' = \frac{150}{(10-5x)^7}\)