3.8 y=(3x²-8)/(2x-4)_

3.8 y = (3x² - 8) / (2x - 4)

Производная функции:

$$y' = \frac{6x \cdot (2x - 4) - (3x^2 - 8) \cdot 2}{(2x - 4)^2} = \frac{12x^2 - 24x - 6x^2 + 16}{(2x - 4)^2} = \frac{6x^2 - 24x + 16}{(2x - 4)^2}$$

Ответ: $$y' = \frac{6x^2 - 24x + 16}{(2x - 4)^2}$$