Решение:
- \( (\frac{3}{16} + \frac{1}{5}) : 32 \)
- \( \frac{3}{16} + \frac{1}{5} = \frac{3 × 5 + 1 × 16}{16 × 5} = \frac{15 + 16}{80} = \frac{31}{80} \)
- \( \frac{31}{80} : 32 = \frac{31}{80 × 32} = \frac{31}{2560} \)
- \( (\frac{7}{20} - \frac{3}{10}) : 11 \)
- \( \frac{7}{20} - \frac{3}{10} = \frac{7}{20} - \frac{3 × 2}{10 × 2} = \frac{7}{20} - \frac{6}{20} = \frac{1}{20} \)
- \( \frac{1}{20} : 11 = \frac{1}{20 × 11} = \frac{1}{220} \)
- \( (25 - 35) : 14 = -10 : 14 = -\frac{10}{14} = -\frac{5}{7} \)
- \( (30 + 10) \cdot 6 = 40 × 6 = 240 \)
Ответ: 1) \( \frac{31}{2560} \); 2) \( \frac{1}{220} \); 3) \( -\frac{5}{7} \); 4) 240.