a) $$(x+1)(x+2)(x+3)=(x^2+x+2x+2)(x+3)=(x^2+3x+2)(x+3)=x^3+3x^2+3x^2+9x+2x+6=x^3+6x^2+11x+6$$
б) $$(a-1)(a-4)(a+5)=(a^2-a-4a+4)(a+5)=(a^2-5a+4)(a+5)=a^3-5a^2+4a+5a^2-25a+20=a^3-21a+20$$
Ответ:
a) $$x^3+6x^2+11x+6$$ b) $$a^3-21a+20$$