ГДЗ по геометрии 9 класс Атанасян Задание 1114

\[\boxed{\mathbf{1114.ОК\ ГДЗ - домашка\ на}\ 5}\]

\[Формула:\]

\[S = \pi R^{2}\ и\ R = \sqrt{\frac{S}{\pi}};где\ \pi = 3,14.\]

\[1)\ S = 3,14 \bullet 2^{2} = 3,14 \bullet 4 =\]

\[= 12,56;\]

\[2)\ S = 3,14 \bullet 5^{2} = 3,14 \bullet 25 =\]

\[= 78,5;\]

\[3)\ R = \sqrt{\frac{9}{3,14}} = 1,69;\]

\[4)\ S = 3,14 \bullet \left( \frac{2}{7} \right)^{2} = \frac{3,14 \bullet 4}{49} =\]

\[= 0,26;\]

\[5)\ R = \sqrt{\frac{49\pi}{\pi}} = \sqrt{49} = 7;\]

\[6)\ S = 3,14 \bullet {54,3}^{2} = 9258,26;\]

\[7)\ S = 3,14 \bullet {\sqrt{3}}^{2} = 3,14 \bullet 3 =\]

\[= 9,42;\]

\[8)\ R = \sqrt{\frac{6,25}{3,14}} = 1,41.\]